![]() ![]() Note: Whenever we face such types of questions the key concept we have to remember is that always recall the formula of permutation which is stated above and always recall that in a English alphabets there are 5 vowels which are given as, A, E, I, O, and U, so according to this find out the number of vowels present in the given word. ![]() So the total number of words such that vowels come in odd places are 576. Vowel Diacritics () When we join a vowel with a consonant, we use the short form of that vowel (Vowel Diacritics). A diacritic can be added above or below a letter. ![]() Hint: In this particular question use the concept that the number of ways to arrange r different objects from n different objects is equal to $ \right) = 576$ Words. Diacritic is a sign that can be added to a letter to change its pronunciation. ![]()
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